Parameter range of stars:
- mass: $0.08-\sim120\,\text{M}_\odot$
- Radii: $0.01-\sim500\,\text{R}_\odot$
- Temp: $300-200,000\,\text{K}$
- Luminosity: $10^{-4}-10^6\,\text{L}_\odot$
Spectral classification scheme in order of temperature:
Class | Spectrum | Colour | Temperature |
---|---|---|---|
O | ionized and neutral helium, weakened hydrogen | Bluish | above $31000$ K |
B | neutral helium, stronger hydrogen | Blue-white | $9750-31000$ K |
A | strong hydrogen, ionized metals | White | $7100-9750$ K |
F | weaker hydrogen, ionized metals | Yellowish-white | $5950-7100$ K |
G | still weaker hydrogen, ionized and neutral metals | Yellowish | $5250-5950$ K |
K | weak hydrogen, neutral metals | Orange | $3800-5250$ K |
M | little or no hydrogen, neutral metals, molecules | Reddish | $2200-3800$ K |
$$ E_n\propto-\frac{1}{n^2} $$
The wavelength of the hydrogen line transitions are given by:
$$ \frac{1}{\lambda}=R\left(\frac{1}{n^2_1}-\frac{1}{n^2_2}\right) $$
Series names
- Transitions to $n_1=1$ are called Lyman series
- $n_1=2$ The Balmer series
- $\Delta n =1$ are indicated with $\alpha$
- $\Delta n=2$ are indicated with $\beta$ etc…
<aside> <img src="https://s3-us-west-2.amazonaws.com/secure.notion-static.com/5a2e0a65-8d23-422e-99e1-3adf844dd3ee/dynamic_time_scale.png" alt="https://s3-us-west-2.amazonaws.com/secure.notion-static.com/5a2e0a65-8d23-422e-99e1-3adf844dd3ee/dynamic_time_scale.png" width="40px" /> The dynamic time scale: The time a star would take to collapse into itself if there was only the gravitational force acting on it
$$ t_{\text{dyn}}\approx\sqrt{\frac{1}{G\bar{\rho}}} $$
<aside> <img src="https://s3-us-west-2.amazonaws.com/secure.notion-static.com/d671af2c-a118-44e2-b431-157be87d1d22/Hydrostatic.png" alt="https://s3-us-west-2.amazonaws.com/secure.notion-static.com/d671af2c-a118-44e2-b431-157be87d1d22/Hydrostatic.png" width="40px" /> Hydrostatic equilibrium: Stars must satisfy the following equation to a very high accuracy otherwise they would be unstable, in other words the pressure gradient needs to equal the gravitational force
$$ \frac{\text{d}P}{\text{d}r}=-\frac{Gm(r)\rho(r)}{r^2} $$
$$ \begin{aligned}P&=nkT\\\text{or: }\quad PV&=nRT\end{aligned} $$